Base | Representation |
---|---|
bin | 100101010100000110… |
… | …001100110101010001 |
3 | 10211102020112020102101 |
4 | 211110012030311101 |
5 | 1124023244222413 |
6 | 30223401120401 |
7 | 2615602061455 |
oct | 452406146521 |
9 | 124366466371 |
10 | 40065617233 |
11 | 15a9aaa6264 |
12 | 7921a89101 |
13 | 3a16848225 |
14 | 1d211ac665 |
15 | 1097648edd |
hex | 95418cd51 |
40065617233 has 4 divisors (see below), whose sum is σ = 40074680128. Its totient is φ = 40056554340.
The previous prime is 40065617231. The next prime is 40065617237. The reversal of 40065617233 is 33271656004.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 40065617233 - 21 = 40065617231 is a prime.
It is a super-2 number, since 2×400656172332 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 40065617192 and 40065617201.
It is not an unprimeable number, because it can be changed into a prime (40065617231) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4524813 + ... + 4533658.
It is an arithmetic number, because the mean of its divisors is an integer number (10018670032).
Almost surely, 240065617233 is an apocalyptic number.
It is an amenable number.
40065617233 is a deficient number, since it is larger than the sum of its proper divisors (9062895).
40065617233 is an equidigital number, since it uses as much as digits as its factorization.
40065617233 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9062894.
The product of its (nonzero) digits is 90720, while the sum is 37.
The spelling of 40065617233 in words is "forty billion, sixty-five million, six hundred seventeen thousand, two hundred thirty-three".
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