Base | Representation |
---|---|
bin | 10010001111001001111100… |
… | …01000101010101111011001 |
3 | 12020222211020121210202010002 |
4 | 21013210332020222233121 |
5 | 20224022223414233421 |
6 | 221143044515502345 |
7 | 11306233331332025 |
oct | 1107447610525731 |
9 | 166884217722102 |
10 | 40103152102361 |
11 | 11861718969347 |
12 | 45b83145b79b5 |
13 | 194b93214551a |
14 | 9c9008017385 |
15 | 498295a42b0b |
hex | 24793e22abd9 |
40103152102361 has 4 divisors (see below), whose sum is σ = 40103177993472. Its totient is φ = 40103126211252.
The previous prime is 40103152102243. The next prime is 40103152102379. The reversal of 40103152102361 is 16320125130104.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-40103152102361 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (40103152192361) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10463561 + ... + 13772886.
It is an arithmetic number, because the mean of its divisors is an integer number (10025794498368).
Almost surely, 240103152102361 is an apocalyptic number.
It is an amenable number.
40103152102361 is a deficient number, since it is larger than the sum of its proper divisors (25891111).
40103152102361 is a wasteful number, since it uses less digits than its factorization.
40103152102361 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25891110.
The product of its (nonzero) digits is 4320, while the sum is 29.
Adding to 40103152102361 its reverse (16320125130104), we get a palindrome (56423277232465).
The spelling of 40103152102361 in words is "forty trillion, one hundred three billion, one hundred fifty-two million, one hundred two thousand, three hundred sixty-one".
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