4010430113 has 4 divisors (see below), whose sum is σ = 4016151828. Its totient is φ = 4004708400.

The previous prime is 4010430089. The next prime is 4010430143. The reversal of 4010430113 is 3110340104.

4010430113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3702357409 + 308072704 = 60847^2 + 17552^2 .

It is a cyclic number.

It is not a de Polignac number, because 4010430113 - 2⁶ = 4010430049 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 4010430091 and 4010430100.

It is not an unprimeable number, because it can be changed into a prime (4010430143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2859806 + ... + 2861207.

It is an arithmetic number, because the mean of its divisors is an integer number (1004037957).

Almost surely, 2^4010430113 is an apocalyptic number.

It is an amenable number.

4010430113 is a deficient number, since it is larger than the sum of its proper divisors (5721715).

4010430113 is an equidigital number, since it uses as much as digits as its factorization.

4010430113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5721714.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 4010430113 is about 63327.9568042425. The cubic root of 4010430113 is about 1588.7795855022.

Adding to 4010430113 its reverse (3110340104), we get a palindrome (7120770217).

Subtracting from 4010430113 its reverse (3110340104), we obtain a palindrome (900090009).

The spelling of 4010430113 in words is "four billion, ten million, four hundred thirty thousand, one hundred thirteen".