40113433 has 4 divisors (see below), whose sum is σ = 40126720. Its totient is φ = 40100148.

The previous prime is 40113413. The next prime is 40113461. The reversal of 40113433 is 33431104.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 40113433 - 2²⁵ = 6559001 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 40113433.

It is not an unprimeable number, because it can be changed into a prime (40113413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 316 + ... + 8962.

It is an arithmetic number, because the mean of its divisors is an integer number (10031680).

Almost surely, 2^40113433 is an apocalyptic number.

It is an amenable number.

40113433 is a deficient number, since it is larger than the sum of its proper divisors (13287).

40113433 is an equidigital number, since it uses as much as digits as its factorization.

40113433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13286.

The product of its (nonzero) digits is 432, while the sum is 19.

The square root of 40113433 is about 6333.5166376982. The cubic root of 40113433 is about 342.3181637304.

Adding to 40113433 its reverse (33431104), we get a palindrome (73544537).

The spelling of 40113433 in words is "forty million, one hundred thirteen thousand, four hundred thirty-three".