Base | Representation |
---|---|
bin | 111010011000100000011… |
… | …101010001101101110001 |
3 | 112012112210020121022002102 |
4 | 322120200131101231301 |
5 | 1011213131231000423 |
6 | 12311035122430145 |
7 | 562601122215062 |
oct | 72304035215561 |
9 | 15175706538072 |
10 | 4012044000113 |
11 | 1307553276176 |
12 | 549689502355 |
13 | 2314460c7716 |
14 | dc280b32569 |
15 | 6e56851cc28 |
hex | 3a620751b71 |
4012044000113 has 16 divisors (see below), whose sum is σ = 4046724403200. Its totient is φ = 3977508971520.
The previous prime is 4012044000071. The next prime is 4012044000121. The reversal of 4012044000113 is 3110004402104.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4012044000113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4012044000413) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 108623633 + ... + 108660561.
It is an arithmetic number, because the mean of its divisors is an integer number (252920275200).
Almost surely, 24012044000113 is an apocalyptic number.
It is an amenable number.
4012044000113 is a deficient number, since it is larger than the sum of its proper divisors (34680403087).
4012044000113 is a wasteful number, since it uses less digits than its factorization.
4012044000113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38872.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 4012044000113 its reverse (3110004402104), we get a palindrome (7122048402217).
The spelling of 4012044000113 in words is "four trillion, twelve billion, forty-four million, one hundred thirteen", and thus it is an aban number.
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