401213142131 has 4 divisors (see below), whose sum is σ = 401214603552. Its totient is φ = 401211680712.

The previous prime is 401213142107. The next prime is 401213142199. The reversal of 401213142131 is 131241312104.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 401213142131 - 2¹⁰ = 401213141107 is a prime.

It is a super-2 number, since 2×401213142131² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 401213142097 and 401213142106.

It is not an unprimeable number, because it can be changed into a prime (401213142431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 181115 + ... + 913908.

It is an arithmetic number, because the mean of its divisors is an integer number (100303650888).

Almost surely, 2^401213142131 is an apocalyptic number.

401213142131 is a deficient number, since it is larger than the sum of its proper divisors (1461421).

401213142131 is a wasteful number, since it uses less digits than its factorization.

401213142131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1461420.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 401213142131 its reverse (131241312104), we get a palindrome (532454454235).

The spelling of 401213142131 in words is "four hundred one billion, two hundred thirteen million, one hundred forty-two thousand, one hundred thirty-one".