4012142443233 has 4 divisors (see below), whose sum is σ = 5349523257648. Its totient is φ = 2674761628820.

The previous prime is 4012142443163. The next prime is 4012142443247. The reversal of 4012142443233 is 3323442412104.

4012142443233 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4012142443233 - 2³² = 4007847475937 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4012142443194 and 4012142443203.

It is not an unprimeable number, because it can be changed into a prime (4012142443333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 668690407203 + ... + 668690407208.

It is an arithmetic number, because the mean of its divisors is an integer number (1337380814412).

Almost surely, 2^{4012142443233} is an apocalyptic number.

It is an amenable number.

4012142443233 is a deficient number, since it is larger than the sum of its proper divisors (1337380814415).

4012142443233 is a wasteful number, since it uses less digits than its factorization.

4012142443233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1337380814414.

The product of its (nonzero) digits is 55296, while the sum is 33.

Adding to 4012142443233 its reverse (3323442412104), we get a palindrome (7335584855337).

The spelling of 4012142443233 in words is "four trillion, twelve billion, one hundred forty-two million, four hundred forty-three thousand, two hundred thirty-three".