Base | Representation |
---|---|
bin | 10010001111101111010011… |
… | …11011100101110101110001 |
3 | 12021001202000210020011021011 |
4 | 21013313221323211311301 |
5 | 20224334320320143003 |
6 | 221200203344430521 |
7 | 11310543436502542 |
oct | 1107675173456561 |
9 | 167052023204234 |
10 | 40123214224753 |
11 | 1186a183468890 |
12 | 4600193318441 |
13 | 19507ab66116a |
14 | 9c9d8c6704c9 |
15 | 498a6be8046d |
hex | 247de9ee5d71 |
40123214224753 has 8 divisors (see below), whose sum is σ = 43868264191200. Its totient is φ = 36394411764480.
The previous prime is 40123214224741. The next prime is 40123214224759. The reversal of 40123214224753 is 35742241232104.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 40123214224753 - 221 = 40123212127601 is a prime.
It is a super-2 number, since 2×401232142247532 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (40123214224759) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4061871375 + ... + 4061881252.
It is an arithmetic number, because the mean of its divisors is an integer number (5483533023900).
Almost surely, 240123214224753 is an apocalyptic number.
It is an amenable number.
40123214224753 is a deficient number, since it is larger than the sum of its proper divisors (3745049966447).
40123214224753 is a wasteful number, since it uses less digits than its factorization.
40123214224753 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8123753087.
The product of its (nonzero) digits is 322560, while the sum is 40.
Adding to 40123214224753 its reverse (35742241232104), we get a palindrome (75865455456857).
The spelling of 40123214224753 in words is "forty trillion, one hundred twenty-three billion, two hundred fourteen million, two hundred twenty-four thousand, seven hundred fifty-three".
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