Base | Representation |
---|---|
bin | 111010011000110110111… |
… | …011111011010000000001 |
3 | 112012120202112020122120201 |
4 | 322120312323323100001 |
5 | 1011214414302231223 |
6 | 12311140354005201 |
7 | 562613351620555 |
oct | 72306673732001 |
9 | 15176675218521 |
10 | 4012421133313 |
11 | 13077271429aa |
12 | 549773876801 |
13 | 2314a6290a68 |
14 | dc2b8c63865 |
15 | 6e58b6b5ead |
hex | 3a636efb401 |
4012421133313 has 4 divisors (see below), whose sum is σ = 4014041007060. Its totient is φ = 4010801259568.
The previous prime is 4012421133271. The next prime is 4012421133323. The reversal of 4012421133313 is 3133311242104.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 2004509461249 + 2007911672064 = 1415807^2 + 1417008^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4012421133313 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4012421133323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 809933158 + ... + 809938111.
It is an arithmetic number, because the mean of its divisors is an integer number (1003510251765).
Almost surely, 24012421133313 is an apocalyptic number.
It is an amenable number.
4012421133313 is a deficient number, since it is larger than the sum of its proper divisors (1619873747).
4012421133313 is a wasteful number, since it uses less digits than its factorization.
4012421133313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1619873746.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 4012421133313 its reverse (3133311242104), we get a palindrome (7145732375417).
The spelling of 4012421133313 in words is "four trillion, twelve billion, four hundred twenty-one million, one hundred thirty-three thousand, three hundred thirteen".
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