Search a number
-
+
40130025121 = 172360589713
BaseRepresentation
bin100101010111111011…
…111001011010100001
310211120201201111102201
4211113323321122201
51124141241300441
630234021413201
72620313404534
oct452773713241
9124521644381
1040130025121
111602339791a
12793b56a201
133a26ca95c4
141d29976a1b
15109d11cc31
hex957ef96a1

40130025121 has 4 divisors (see below), whose sum is σ = 42490614852. Its totient is φ = 37769435392.

The previous prime is 40130025049. The next prime is 40130025137. The reversal of 40130025121 is 12152003104.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 20897882721 + 19232142400 = 144561^2 + 138680^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-40130025121 is a prime.

It is a super-2 number, since 2×401300251212 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (40130025421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1180294840 + ... + 1180294873.

It is an arithmetic number, because the mean of its divisors is an integer number (10622653713).

Almost surely, 240130025121 is an apocalyptic number.

It is an amenable number.

40130025121 is a deficient number, since it is larger than the sum of its proper divisors (2360589731).

40130025121 is a wasteful number, since it uses less digits than its factorization.

40130025121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2360589730.

The product of its (nonzero) digits is 240, while the sum is 19.

Adding to 40130025121 its reverse (12152003104), we get a palindrome (52282028225).

The spelling of 40130025121 in words is "forty billion, one hundred thirty million, twenty-five thousand, one hundred twenty-one".

Divisors: 1 17 2360589713 40130025121