4013013401 has 4 divisors (see below), whose sum is σ = 4027501092. Its totient is φ = 3998525712.

The previous prime is 4013013383. The next prime is 4013013413. The reversal of 4013013401 is 1043103104.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 576240025 + 3436773376 = 24005^2 + 58624^2 .

It is a cyclic number.

It is not a de Polignac number, because 4013013401 - 2²² = 4008819097 is a prime.

It is a super-2 number, since 2×4013013401² = 32208553113211173602, which contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 4013013401.

It is not an unprimeable number, because it can be changed into a prime (4013013461) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7243430 + ... + 7243983.

It is an arithmetic number, because the mean of its divisors is an integer number (1006875273).

Almost surely, 2^4013013401 is an apocalyptic number.

It is an amenable number.

4013013401 is a deficient number, since it is larger than the sum of its proper divisors (14487691).

4013013401 is a wasteful number, since it uses less digits than its factorization.

4013013401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14487690.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 4013013401 is about 63348.3496312256. The cubic root of 4013013401 is about 1589.1206457037.

Adding to 4013013401 its reverse (1043103104), we get a palindrome (5056116505).

The spelling of 4013013401 in words is "four billion, thirteen million, thirteen thousand, four hundred one".