4013103001 has 4 divisors (see below), whose sum is σ = 4110983604. Its totient is φ = 3915222400.

The previous prime is 4013102987. The next prime is 4013103041. The reversal of 4013103001 is 1003013104.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 840710025 + 3172392976 = 28995^2 + 56324^2 .

It is a cyclic number.

It is not a de Polignac number, because 4013103001 - 2¹⁵ = 4013070233 is a prime.

It is a super-2 number, since 2×4013103001² = 32209991393270412002, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4013103041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48940240 + ... + 48940321.

It is an arithmetic number, because the mean of its divisors is an integer number (1027745901).

Almost surely, 2^4013103001 is an apocalyptic number.

4013103001 is a gapful number since it is divisible by the number (41) formed by its first and last digit.

It is an amenable number.

4013103001 is a deficient number, since it is larger than the sum of its proper divisors (97880603).

4013103001 is an equidigital number, since it uses as much as digits as its factorization.

4013103001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 97880602.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 4013103001 is about 63349.0568280223. The cubic root of 4013103001 is about 1589.1324725726.

Adding to 4013103001 its reverse (1003013104), we get a palindrome (5016116105).

The spelling of 4013103001 in words is "four billion, thirteen million, one hundred three thousand, one".