401314251113 has 4 divisors (see below), whose sum is σ = 401754772608. Its totient is φ = 400873729620.

The previous prime is 401314251103. The next prime is 401314251131. The reversal of 401314251113 is 311152413104.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 401314251113 - 2⁶ = 401314251049 is a prime.

It is a super-2 number, since 2×401314251113² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (401314251103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 220259381 + ... + 220261202.

It is an arithmetic number, because the mean of its divisors is an integer number (100438693152).

Almost surely, 2^401314251113 is an apocalyptic number.

It is an amenable number.

401314251113 is a deficient number, since it is larger than the sum of its proper divisors (440521495).

401314251113 is an equidigital number, since it uses as much as digits as its factorization.

401314251113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 440521494.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 401314251113 its reverse (311152413104), we get a palindrome (712466664217).

The spelling of 401314251113 in words is "four hundred one billion, three hundred fourteen million, two hundred fifty-one thousand, one hundred thirteen".