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4013400310041 = 33767505970199
BaseRepresentation
bin111010011001110001010…
…011001100000100011001
3112012200021202201222112110
4322121301103030010121
51011223420434410131
612311421453102533
7562646541523323
oct72316123140431
915180252658473
104013400310041
111308089933971
125499a7787a49
132316010b9b85
14dc36cd10613
156e5e7632646
hex3a6714cc119

4013400310041 has 16 divisors (see below), whose sum is σ = 5353755264000. Its totient is φ = 2674323097488.

The previous prime is 4013400310027. The next prime is 4013400310057. The reversal of 4013400310041 is 1400130043104.

It is not a de Polignac number, because 4013400310041 - 215 = 4013400277273 is a prime.

It is a super-2 number, since 2×40134003100412 (a number of 26 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (4013400310141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 57136660 + ... + 57206858.

It is an arithmetic number, because the mean of its divisors is an integer number (334609704000).

Almost surely, 24013400310041 is an apocalyptic number.

It is an amenable number.

4013400310041 is a deficient number, since it is larger than the sum of its proper divisors (1340354953959).

4013400310041 is a wasteful number, since it uses less digits than its factorization.

4013400310041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 79028.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 4013400310041 its reverse (1400130043104), we get a palindrome (5413530353145).

The spelling of 4013400310041 in words is "four trillion, thirteen billion, four hundred million, three hundred ten thousand, forty-one".

Divisors: 1 3 3767 5059 11301 15177 70199 210597 19057253 57171759 264439633 355136741 793318899 1065410223 1337800103347 4013400310041