Base | Representation |
---|---|
bin | 111010011001110001010… |
… | …011001100000100011001 |
3 | 112012200021202201222112110 |
4 | 322121301103030010121 |
5 | 1011223420434410131 |
6 | 12311421453102533 |
7 | 562646541523323 |
oct | 72316123140431 |
9 | 15180252658473 |
10 | 4013400310041 |
11 | 1308089933971 |
12 | 5499a7787a49 |
13 | 2316010b9b85 |
14 | dc36cd10613 |
15 | 6e5e7632646 |
hex | 3a6714cc119 |
4013400310041 has 16 divisors (see below), whose sum is σ = 5353755264000. Its totient is φ = 2674323097488.
The previous prime is 4013400310027. The next prime is 4013400310057. The reversal of 4013400310041 is 1400130043104.
It is not a de Polignac number, because 4013400310041 - 215 = 4013400277273 is a prime.
It is a super-2 number, since 2×40134003100412 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (4013400310141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 57136660 + ... + 57206858.
It is an arithmetic number, because the mean of its divisors is an integer number (334609704000).
Almost surely, 24013400310041 is an apocalyptic number.
It is an amenable number.
4013400310041 is a deficient number, since it is larger than the sum of its proper divisors (1340354953959).
4013400310041 is a wasteful number, since it uses less digits than its factorization.
4013400310041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 79028.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 4013400310041 its reverse (1400130043104), we get a palindrome (5413530353145).
The spelling of 4013400310041 in words is "four trillion, thirteen billion, four hundred million, three hundred ten thousand, forty-one".
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