4013440113 has 8 divisors (see below), whose sum is σ = 5352076800. Its totient is φ = 2675215088.

The previous prime is 4013440111. The next prime is 4013440117. The reversal of 4013440113 is 3110443104.

4013440113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 4013440113 - 2¹ = 4013440111 is a prime.

It is a super-2 number, since 2×4013440113² = 32215403081274905538, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 4013440113.

It is not an unprimeable number, because it can be changed into a prime (4013440111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 79398 + ... + 119711.

It is an arithmetic number, because the mean of its divisors is an integer number (669009600).

Almost surely, 2^4013440113 is an apocalyptic number.

It is an amenable number.

4013440113 is a deficient number, since it is larger than the sum of its proper divisors (1338636687).

4013440113 is a wasteful number, since it uses less digits than its factorization.

4013440113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 205831.

The product of its (nonzero) digits is 576, while the sum is 21.

The square root of 4013440113 is about 63351.7175221004. The cubic root of 4013440113 is about 1589.1769685338.

Adding to 4013440113 its reverse (3110443104), we get a palindrome (7123883217).

The spelling of 4013440113 in words is "four billion, thirteen million, four hundred forty thousand, one hundred thirteen".