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4014312013201 = 7573473144743
BaseRepresentation
bin111010011010100111101…
…001000011110110010001
3112012202122022021022011011
4322122213221003312101
51011232302333410301
612312052142050521
7563011252054120
oct72324751036621
915182568238134
104014312013201
111308507529a56
1254a000b79a41
13231717c503b9
14dc418035ab7
156e64c6c1a51
hex3a6a7a43d91

4014312013201 has 4 divisors (see below), whose sum is σ = 4587785157952. Its totient is φ = 3440838868452.

The previous prime is 4014312013193. The next prime is 4014312013213. The reversal of 4014312013201 is 1023102134104.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4014312013201 - 23 = 4014312013193 is a prime.

It is a super-2 number, since 2×40143120132012 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4014312011201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 286736572365 + ... + 286736572378.

It is an arithmetic number, because the mean of its divisors is an integer number (1146946289488).

Almost surely, 24014312013201 is an apocalyptic number.

It is an amenable number.

4014312013201 is a deficient number, since it is larger than the sum of its proper divisors (573473144751).

4014312013201 is an equidigital number, since it uses as much as digits as its factorization.

4014312013201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 573473144750.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 4014312013201 its reverse (1023102134104), we get a palindrome (5037414147305).

The spelling of 4014312013201 in words is "four trillion, fourteen billion, three hundred twelve million, thirteen thousand, two hundred one".

Divisors: 1 7 573473144743 4014312013201