Base | Representation |
---|---|
bin | 10010010010000111111001… |
… | …01011100000001101100001 |
3 | 12021100120110212010220010011 |
4 | 21021003330223200031201 |
5 | 20232210103041344441 |
6 | 221301552211404521 |
7 | 11316503452060516 |
oct | 1111037453401541 |
9 | 167316425126104 |
10 | 40205133153121 |
11 | 118a09a0579182 |
12 | 46140358b3741 |
13 | 19584351c6241 |
14 | 9cdd201dd30d |
15 | 49ac63b4a581 |
hex | 2490fcae0361 |
40205133153121 has 4 divisors (see below), whose sum is σ = 41953182420672. Its totient is φ = 38457083885572.
The previous prime is 40205133153079. The next prime is 40205133153127. The reversal of 40205133153121 is 12135133150204.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 40205133153121 - 213 = 40205133144929 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (40205133153127) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 874024633741 + ... + 874024633786.
It is an arithmetic number, because the mean of its divisors is an integer number (10488295605168).
Almost surely, 240205133153121 is an apocalyptic number.
It is an amenable number.
40205133153121 is a deficient number, since it is larger than the sum of its proper divisors (1748049267551).
40205133153121 is a wasteful number, since it uses less digits than its factorization.
40205133153121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1748049267550.
The product of its (nonzero) digits is 10800, while the sum is 31.
The spelling of 40205133153121 in words is "forty trillion, two hundred five billion, one hundred thirty-three million, one hundred fifty-three thousand, one hundred twenty-one".
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