Search a number
-
+
40220013443 = 67153598931
BaseRepresentation
bin100101011101010011…
…001011001110000011
310211211000001101012112
4211131103023032003
51124332310412233
630250554245535
72622455321261
oct453523131603
9124730041175
1040220013443
111606a170435
1279657268ab
133a3c82612c
141d378bd431
1510a5e96048
hex95d4cb383

40220013443 has 4 divisors (see below), whose sum is σ = 40220679528. Its totient is φ = 40219347360.

The previous prime is 40220013403. The next prime is 40220013461. The reversal of 40220013443 is 34431002204.

40220013443 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-40220013443 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (40220013403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 232313 + ... + 366618.

It is an arithmetic number, because the mean of its divisors is an integer number (10055169882).

Almost surely, 240220013443 is an apocalyptic number.

40220013443 is a deficient number, since it is larger than the sum of its proper divisors (666085).

40220013443 is an equidigital number, since it uses as much as digits as its factorization.

40220013443 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 666084.

The product of its (nonzero) digits is 2304, while the sum is 23.

Adding to 40220013443 its reverse (34431002204), we get a palindrome (74651015647).

The spelling of 40220013443 in words is "forty billion, two hundred twenty million, thirteen thousand, four hundred forty-three".

Divisors: 1 67153 598931 40220013443