Base | Representation |
---|---|
bin | 111010100001110010100… |
… | …110010001000011011011 |
3 | 112020111111221012022212101 |
4 | 322201302212101003123 |
5 | 1011344040034214003 |
6 | 12315404204024231 |
7 | 563403131055232 |
oct | 72416246210333 |
9 | 15214457168771 |
10 | 4022012023003 |
11 | 13107a8a2a317 |
12 | 54b5ab832077 |
13 | 23237429a010 |
14 | dc94892db19 |
15 | 6e94d6b111d |
hex | 3a8729910db |
4022012023003 has 16 divisors (see below), whose sum is σ = 4344856064640. Its totient is φ = 3701100848256.
The previous prime is 4022012022967. The next prime is 4022012023037. The reversal of 4022012023003 is 3003202102204.
It is a cyclic number.
It is not a de Polignac number, because 4022012023003 - 233 = 4013422088411 is a prime.
It is a super-3 number, since 3×40220120230033 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (4022012023063) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9280126 + ... + 9703852.
It is an arithmetic number, because the mean of its divisors is an integer number (271553504040).
Almost surely, 24022012023003 is an apocalyptic number.
4022012023003 is a deficient number, since it is larger than the sum of its proper divisors (322844041637).
4022012023003 is a wasteful number, since it uses less digits than its factorization.
4022012023003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 426006.
The product of its (nonzero) digits is 576, while the sum is 19.
Adding to 4022012023003 its reverse (3003202102204), we get a palindrome (7025214125207).
The spelling of 4022012023003 in words is "four trillion, twenty-two billion, twelve million, twenty-three thousand, three".
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