Base | Representation |
---|---|
bin | 111010100010110100000… |
… | …100000001011100000011 |
3 | 112020121100110212201211200 |
4 | 322202310010001130003 |
5 | 1011403312221424103 |
6 | 12320105200512243 |
7 | 563442265451505 |
oct | 72426404013403 |
9 | 15217313781750 |
10 | 4023110342403 |
11 | 13112119a69a9 |
12 | 54b85761b683 |
13 | 2324ba9aca59 |
14 | dca10751d75 |
15 | 6e9b4d140a3 |
hex | 3a8b4101703 |
4023110342403 has 6 divisors (see below), whose sum is σ = 5811159383484. Its totient is φ = 2682073561596.
The previous prime is 4023110342393. The next prime is 4023110342479. The reversal of 4023110342403 is 3042430113204.
4023110342403 is a `hidden beast` number, since 4 + 0 + 2 + 311 + 0 + 342 + 4 + 0 + 3 = 666.
It is not a de Polignac number, because 4023110342403 - 218 = 4023110080259 is a prime.
It is not an unprimeable number, because it can be changed into a prime (4023117342403) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 223506130125 + ... + 223506130142.
It is an arithmetic number, because the mean of its divisors is an integer number (968526563914).
Almost surely, 24023110342403 is an apocalyptic number.
4023110342403 is a deficient number, since it is larger than the sum of its proper divisors (1788049041081).
4023110342403 is a wasteful number, since it uses less digits than its factorization.
4023110342403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 447012260273 (or 447012260270 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 4023110342403 its reverse (3042430113204), we get a palindrome (7065540455607).
The spelling of 4023110342403 in words is "four trillion, twenty-three billion, one hundred ten million, three hundred forty-two thousand, four hundred three".
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