Base | Representation |
---|---|
bin | 10010010010111111110001… |
… | …11101100010111100101011 |
3 | 12021110102220202221022201020 |
4 | 21021133320331202330223 |
5 | 20233203024144421011 |
6 | 221323433251023523 |
7 | 11321615111151252 |
oct | 1111377075427453 |
9 | 167412822838636 |
10 | 40235135545131 |
11 | 119026970a637a |
12 | 4619a0959aba3 |
13 | 195b206c18017 |
14 | 9d1568aab799 |
15 | 49b91ca98006 |
hex | 2497f8f62f2b |
40235135545131 has 4 divisors (see below), whose sum is σ = 53646847393512. Its totient is φ = 26823423696752.
The previous prime is 40235135545127. The next prime is 40235135545139. The reversal of 40235135545131 is 13154553153204.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 40235135545131 - 22 = 40235135545127 is a prime.
It is a super-2 number, since 2×402351355451312 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (40235135545139) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6705855924186 + ... + 6705855924191.
It is an arithmetic number, because the mean of its divisors is an integer number (13411711848378).
Almost surely, 240235135545131 is an apocalyptic number.
40235135545131 is a deficient number, since it is larger than the sum of its proper divisors (13411711848381).
40235135545131 is a wasteful number, since it uses less digits than its factorization.
40235135545131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13411711848380.
The product of its (nonzero) digits is 540000, while the sum is 42.
Adding to 40235135545131 its reverse (13154553153204), we get a palindrome (53389688698335).
The spelling of 40235135545131 in words is "forty trillion, two hundred thirty-five billion, one hundred thirty-five million, five hundred forty-five thousand, one hundred thirty-one".
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