Base | Representation |
---|---|
bin | 111010100011110111011… |
… | …101111110101101010001 |
3 | 112020201021021211021212011 |
4 | 322203313131332231101 |
5 | 1011413121223023213 |
6 | 12320413315302521 |
7 | 563512306661140 |
oct | 72436735765521 |
9 | 15221237737764 |
10 | 4024241220433 |
11 | 1311742291345 |
12 | 54bb122aaa41 |
13 | 23263b082255 |
14 | dcabaa0b757 |
15 | 6ea2e24903d |
hex | 3a8f777eb51 |
4024241220433 has 16 divisors (see below), whose sum is σ = 4643939978496. Its totient is φ = 3415746493440.
The previous prime is 4024241220431. The next prime is 4024241220457. The reversal of 4024241220433 is 3340221424204.
It is a cyclic number.
It is not a de Polignac number, because 4024241220433 - 21 = 4024241220431 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4024241220395 and 4024241220404.
It is not an unprimeable number, because it can be changed into a prime (4024241220431) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 26862585 + ... + 27011977.
It is an arithmetic number, because the mean of its divisors is an integer number (290246248656).
Almost surely, 24024241220433 is an apocalyptic number.
It is an amenable number.
4024241220433 is a deficient number, since it is larger than the sum of its proper divisors (619698758063).
4024241220433 is a wasteful number, since it uses less digits than its factorization.
4024241220433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 186864.
The product of its (nonzero) digits is 36864, while the sum is 31.
Adding to 4024241220433 its reverse (3340221424204), we get a palindrome (7364462644637).
The spelling of 4024241220433 in words is "four trillion, twenty-four billion, two hundred forty-one million, two hundred twenty thousand, four hundred thirty-three".
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