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40254435340313 = 197512038096063
BaseRepresentation
bin10010010011100011101110…
…10100011011000000011001
312021112021201210220111112012
421021301313110123000121
520234012040421342223
6221340344324355305
711323200301541555
oct1111616724330031
9167467653814465
1040254435340313
111190a8a0356127
1246216b4b45b35
13195cc9151127c
149d2479da4865
1549c19c100c78
hex249c7751b019

40254435340313 has 4 divisors (see below), whose sum is σ = 40256473456128. Its totient is φ = 40252397224500.

The previous prime is 40254435340289. The next prime is 40254435340321. The reversal of 40254435340313 is 31304353445204.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 40254435340313 - 220 = 40254434291737 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (40254435340363) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1019028281 + ... + 1019067782.

It is an arithmetic number, because the mean of its divisors is an integer number (10064118364032).

Almost surely, 240254435340313 is an apocalyptic number.

It is an amenable number.

40254435340313 is a deficient number, since it is larger than the sum of its proper divisors (2038115815).

40254435340313 is a wasteful number, since it uses less digits than its factorization.

40254435340313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2038115814.

The product of its (nonzero) digits is 1036800, while the sum is 41.

Adding to 40254435340313 its reverse (31304353445204), we get a palindrome (71558788785517).

The spelling of 40254435340313 in words is "forty trillion, two hundred fifty-four billion, four hundred thirty-five million, three hundred forty thousand, three hundred thirteen".

Divisors: 1 19751 2038096063 40254435340313