Base | Representation |
---|---|
bin | 10010010101001110111111… |
… | …11000111101110011000001 |
3 | 12021201210101021202001110120 |
4 | 21022213133320331303001 |
5 | 20240433011211402223 |
6 | 221423031024250453 |
7 | 11330306354045166 |
oct | 1112473770756301 |
9 | 167653337661416 |
10 | 40312024325313 |
11 | 11932262887a04 |
12 | 46308a7470a29 |
13 | 196553b5c6c60 |
14 | 9d518056c06d |
15 | 49d91cd53be3 |
hex | 24a9dfe3dcc1 |
40312024325313 has 16 divisors (see below), whose sum is σ = 57954436591296. Its totient is φ = 24777183487680.
The previous prime is 40312024325297. The next prime is 40312024325341. The reversal of 40312024325313 is 31352342021304.
It is not a de Polignac number, because 40312024325313 - 24 = 40312024325297 is a prime.
It is not an unprimeable number, because it can be changed into a prime (40312024320313) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 629469595 + ... + 629533632.
It is an arithmetic number, because the mean of its divisors is an integer number (3622152286956).
Almost surely, 240312024325313 is an apocalyptic number.
It is an amenable number.
40312024325313 is a deficient number, since it is larger than the sum of its proper divisors (17642412265983).
40312024325313 is a wasteful number, since it uses less digits than its factorization.
40312024325313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1259004064.
The product of its (nonzero) digits is 51840, while the sum is 33.
Adding to 40312024325313 its reverse (31352342021304), we get a palindrome (71664366346617).
The spelling of 40312024325313 in words is "forty trillion, three hundred twelve billion, twenty-four million, three hundred twenty-five thousand, three hundred thirteen".
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