Base | Representation |
---|---|
bin | 111010101010010111000… |
… | …001101000011101001001 |
3 | 112021101021011200000220111 |
4 | 322222113001220131021 |
5 | 1012021411024023423 |
6 | 12323525211154321 |
7 | 564150135035056 |
oct | 72522701503511 |
9 | 15241234600814 |
10 | 4031213111113 |
11 | 131469a786a71 |
12 | 5513391459a1 |
13 | 2331ac5c5956 |
14 | dd17c92c02d |
15 | 6ecdb35e60d |
hex | 3aa97068749 |
4031213111113 has 4 divisors (see below), whose sum is σ = 4031217430480. Its totient is φ = 4031208791748.
The previous prime is 4031213111087. The next prime is 4031213111129. The reversal of 4031213111113 is 3111113121304.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 4031213111113 - 213 = 4031213102921 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4031211111113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 113595 + ... + 2841712.
It is an arithmetic number, because the mean of its divisors is an integer number (1007804357620).
Almost surely, 24031213111113 is an apocalyptic number.
It is an amenable number.
4031213111113 is a deficient number, since it is larger than the sum of its proper divisors (4319367).
4031213111113 is a wasteful number, since it uses less digits than its factorization.
4031213111113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4319366.
The product of its (nonzero) digits is 216, while the sum is 22.
Adding to 4031213111113 its reverse (3111113121304), we get a palindrome (7142326232417).
The spelling of 4031213111113 in words is "four trillion, thirty-one billion, two hundred thirteen million, one hundred eleven thousand, one hundred thirteen".
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