40313122143121 has 4 divisors (see below), whose sum is σ = 40313134921072. Its totient is φ = 40313109365172.

The previous prime is 40313122142981. The next prime is 40313122143131. The reversal of 40313122143121 is 12134122131304.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 40313122143121 - 2⁴⁵ = 5128750054289 is a prime.

It is a super-3 number, since 3×40313122143121³ (a number of 42 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 40313122143121.

It is not an unprimeable number, because it can be changed into a prime (40313122143131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2127610 + ... + 9227836.

It is an arithmetic number, because the mean of its divisors is an integer number (10078283730268).

Almost surely, 2^{40313122143121} is an apocalyptic number.

It is an amenable number.

40313122143121 is a deficient number, since it is larger than the sum of its proper divisors (12777951).

40313122143121 is an equidigital number, since it uses as much as digits as its factorization.

40313122143121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12777950.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 40313122143121 its reverse (12134122131304), we get a palindrome (52447244274425).

The spelling of 40313122143121 in words is "forty trillion, three hundred thirteen billion, one hundred twenty-two million, one hundred forty-three thousand, one hundred twenty-one".