4033120000121 has 4 divisors (see below), whose sum is σ = 4033137286500. Its totient is φ = 4033102713744.

The previous prime is 4033120000087. The next prime is 4033120000123. The reversal of 4033120000121 is 1210000213304.

4033120000121 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2699120410000 + 1333999590121 = 1642900^2 + 1154989^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4033120000121 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 4033120000121.

It is not an unprimeable number, because it can be changed into a prime (4033120000123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8288366 + ... + 8761463.

It is an arithmetic number, because the mean of its divisors is an integer number (1008284321625).

Almost surely, 2^{4033120000121} is an apocalyptic number.

It is an amenable number.

4033120000121 is a deficient number, since it is larger than the sum of its proper divisors (17286379).

4033120000121 is a wasteful number, since it uses less digits than its factorization.

4033120000121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17286378.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 4033120000121 its reverse (1210000213304), we get a palindrome (5243120213425).

The spelling of 4033120000121 in words is "four trillion, thirty-three billion, one hundred twenty million, one hundred twenty-one", and thus it is an aban number.