4034143232113 has 4 divisors (see below), whose sum is σ = 4209540763968. Its totient is φ = 3858745700260.

The previous prime is 4034143232107. The next prime is 4034143232131. The reversal of 4034143232113 is 3112323414304.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4034143232113 - 2²⁵ = 4034109677681 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4034143232143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 87698765893 + ... + 87698765938.

It is an arithmetic number, because the mean of its divisors is an integer number (1052385190992).

Almost surely, 2^{4034143232113} is an apocalyptic number.

It is an amenable number.

4034143232113 is a deficient number, since it is larger than the sum of its proper divisors (175397531855).

4034143232113 is a wasteful number, since it uses less digits than its factorization.

4034143232113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 175397531854.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 4034143232113 its reverse (3112323414304), we get a palindrome (7146466646417).

The spelling of 4034143232113 in words is "four trillion, thirty-four billion, one hundred forty-three million, two hundred thirty-two thousand, one hundred thirteen".