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4034380845147 = 31344793615049
BaseRepresentation
bin111010101101010011110…
…101100101000001011011
3112021200102221022121002020
4322231103311211001123
51012044402444021042
612325211410505523
7564321501241212
oct72552365450133
915250387277066
104034380845147
111315a758a1484
12551a81b952a3
13233595977ca3
14dd39d518079
156ee244d73ec
hex3ab53d6505b

4034380845147 has 4 divisors (see below), whose sum is σ = 5379174460200. Its totient is φ = 2689587230096.

The previous prime is 4034380845097. The next prime is 4034380845161. The reversal of 4034380845147 is 7415480834304.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4034380845147 - 223 = 4034372456539 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 4034380845147.

It is not an unprimeable number, because it can be changed into a prime (4034380845347) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 672396807522 + ... + 672396807527.

It is an arithmetic number, because the mean of its divisors is an integer number (1344793615050).

Almost surely, 24034380845147 is an apocalyptic number.

4034380845147 is a deficient number, since it is larger than the sum of its proper divisors (1344793615053).

4034380845147 is a wasteful number, since it uses less digits than its factorization.

4034380845147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1344793615052.

The product of its (nonzero) digits is 5160960, while the sum is 51.

The spelling of 4034380845147 in words is "four trillion, thirty-four billion, three hundred eighty million, eight hundred forty-five thousand, one hundred forty-seven".

Divisors: 1 3 1344793615049 4034380845147