Search a number
-
+
40344412553 = 311301432663
BaseRepresentation
bin100101100100101101…
…101110000110001001
310212010200010111200222
4211210231232012021
51130111132200203
630311200435425
72625525564014
oct454455560611
9125120114628
1040344412553
1116123407315
12799b318b75
133a5c530483
141d4a22237b
1510b1d6a038
hex964b6e189

40344412553 has 4 divisors (see below), whose sum is σ = 41645845248. Its totient is φ = 39042979860.

The previous prime is 40344412547. The next prime is 40344412621. The reversal of 40344412553 is 35521444304.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 40344412553 - 212 = 40344408457 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (40344412513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 650716301 + ... + 650716362.

It is an arithmetic number, because the mean of its divisors is an integer number (10411461312).

Almost surely, 240344412553 is an apocalyptic number.

It is an amenable number.

40344412553 is a deficient number, since it is larger than the sum of its proper divisors (1301432695).

40344412553 is a wasteful number, since it uses less digits than its factorization.

40344412553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1301432694.

The product of its (nonzero) digits is 115200, while the sum is 35.

Adding to 40344412553 its reverse (35521444304), we get a palindrome (75865856857).

The spelling of 40344412553 in words is "forty billion, three hundred forty-four million, four hundred twelve thousand, five hundred fifty-three".

Divisors: 1 31 1301432663 40344412553