Base | Representation |
---|---|
bin | 111010101111011001100… |
… | …110110100101111011001 |
3 | 112021220020100022210022211 |
4 | 322233121212310233121 |
5 | 1012114002012434223 |
6 | 12330222221315121 |
7 | 564431222300155 |
oct | 72573146645731 |
9 | 15256210283284 |
10 | 4036625124313 |
11 | 1316a17714651 |
12 | 5523a9705aa1 |
13 | 233862910b22 |
14 | dd533600065 |
15 | 7000654dd0d |
hex | 3abd99b4bd9 |
4036625124313 has 16 divisors (see below), whose sum is σ = 4136111907840. Its totient is φ = 3937396239504.
The previous prime is 4036625124307. The next prime is 4036625124379. The reversal of 4036625124313 is 3134215266304.
It is a cyclic number.
It is not a de Polignac number, because 4036625124313 - 25 = 4036625124281 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4036625124383) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 137740020 + ... + 137769322.
It is an arithmetic number, because the mean of its divisors is an integer number (258506994240).
Almost surely, 24036625124313 is an apocalyptic number.
4036625124313 is a gapful number since it is divisible by the number (43) formed by its first and last digit.
It is an amenable number.
4036625124313 is a deficient number, since it is larger than the sum of its proper divisors (99486783527).
4036625124313 is a wasteful number, since it uses less digits than its factorization.
4036625124313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33588.
The product of its (nonzero) digits is 311040, while the sum is 40.
The spelling of 4036625124313 in words is "four trillion, thirty-six billion, six hundred twenty-five million, one hundred twenty-four thousand, three hundred thirteen".
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