Base | Representation |
---|---|
bin | 111010110010100011011… |
… | …001001101000000111001 |
3 | 112022012222021121022011111 |
4 | 322302203121031000321 |
5 | 1012142420200120403 |
6 | 12331542155000321 |
7 | 564611141040640 |
oct | 72624331150071 |
9 | 15265867538144 |
10 | 4040010551353 |
11 | 13183a46a7037 |
12 | 552b934390a1 |
13 | 233c821037aa |
14 | dd775096357 |
15 | 7015387856d |
hex | 3aca364d039 |
4040010551353 has 4 divisors (see below), whose sum is σ = 4617154915840. Its totient is φ = 3462866186868.
The previous prime is 4040010551267. The next prime is 4040010551363. The reversal of 4040010551353 is 3531550100404.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4040010551353 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4040010551363) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 288572182233 + ... + 288572182246.
It is an arithmetic number, because the mean of its divisors is an integer number (1154288728960).
Almost surely, 24040010551353 is an apocalyptic number.
It is an amenable number.
4040010551353 is a deficient number, since it is larger than the sum of its proper divisors (577144364487).
4040010551353 is an equidigital number, since it uses as much as digits as its factorization.
4040010551353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 577144364486.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 4040010551353 its reverse (3531550100404), we get a palindrome (7571560651757).
The spelling of 4040010551353 in words is "four trillion, forty billion, ten million, five hundred fifty-one thousand, three hundred fifty-three".
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