Base | Representation |
---|---|
bin | 111010110010101010001… |
… | …011001010101101110001 |
3 | 112022020021012122222000211 |
4 | 322302222023022231301 |
5 | 1012143133310444213 |
6 | 12332001341144121 |
7 | 564614022015616 |
oct | 72625213125561 |
9 | 15266235588024 |
10 | 4040124312433 |
11 | 1318452937460 |
12 | 55300555b041 |
13 | 233c9c854a41 |
14 | dd78622a50d |
15 | 7015d84a53d |
hex | 3acaa2cab71 |
4040124312433 has 8 divisors (see below), whose sum is σ = 4639377201120. Its totient is φ = 3479532900480.
The previous prime is 4040124312407. The next prime is 4040124312451. The reversal of 4040124312433 is 3342134210404.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 4040124312433 - 213 = 4040124304241 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 4040124312395 and 4040124312404.
It is not an unprimeable number, because it can be changed into a prime (4040124312473) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9665368960 + ... + 9665369377.
It is an arithmetic number, because the mean of its divisors is an integer number (579922150140).
Almost surely, 24040124312433 is an apocalyptic number.
It is an amenable number.
4040124312433 is a deficient number, since it is larger than the sum of its proper divisors (599252888687).
4040124312433 is a wasteful number, since it uses less digits than its factorization.
4040124312433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19330738367.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 4040124312433 its reverse (3342134210404), we get a palindrome (7382258522837).
The spelling of 4040124312433 in words is "four trillion, forty billion, one hundred twenty-four million, three hundred twelve thousand, four hundred thirty-three".
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