Base | Representation |
---|---|
bin | 111010110010110110000… |
… | …001111000000101101001 |
3 | 112022020210001220200012011 |
4 | 322302312001320011221 |
5 | 1012144040220002213 |
6 | 12332033204115521 |
7 | 564621655404016 |
oct | 72626601700551 |
9 | 15266701820164 |
10 | 4040323203433 |
11 | 1318545132190 |
12 | 553060095ba1 |
13 | 234001b1131a |
14 | dd7a480070d |
15 | 7017103603d |
hex | 3acb6078169 |
4040323203433 has 16 divisors (see below), whose sum is σ = 4530353135616. Its totient is φ = 3571514004240.
The previous prime is 4040323203401. The next prime is 4040323203439. The reversal of 4040323203433 is 3343023230404.
It is a cyclic number.
It is not a de Polignac number, because 4040323203433 - 25 = 4040323203401 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4040323203395 and 4040323203404.
It is not an unprimeable number, because it can be changed into a prime (4040323203439) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 19046785 + ... + 19257742.
It is an arithmetic number, because the mean of its divisors is an integer number (283147070976).
Almost surely, 24040323203433 is an apocalyptic number.
4040323203433 is a gapful number since it is divisible by the number (43) formed by its first and last digit.
It is an amenable number.
4040323203433 is a deficient number, since it is larger than the sum of its proper divisors (490029932183).
4040323203433 is a wasteful number, since it uses less digits than its factorization.
4040323203433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38304804.
The product of its (nonzero) digits is 62208, while the sum is 31.
Adding to 4040323203433 its reverse (3343023230404), we get a palindrome (7383346433837).
The spelling of 4040323203433 in words is "four trillion, forty billion, three hundred twenty-three million, two hundred three thousand, four hundred thirty-three".
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