4040434113131 has 16 divisors (see below), whose sum is σ = 4651162931520. Its totient is φ = 3480462036480.

The previous prime is 4040434113109. The next prime is 4040434113137. The reversal of 4040434113131 is 1313114340404.

4040434113131 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 4040434113131 - 2²² = 4040429918827 is a prime.

It is a super-2 number, since 2×4040434113131² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4040434113094 and 4040434113103.

It is not an unprimeable number, because it can be changed into a prime (4040434113137) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 164782346 + ... + 164806863.

It is an arithmetic number, because the mean of its divisors is an integer number (290697683220).

Almost surely, 2^{4040434113131} is an apocalyptic number.

4040434113131 is a gapful number since it is divisible by the number (41) formed by its first and last digit.

4040434113131 is a deficient number, since it is larger than the sum of its proper divisors (610728818389).

4040434113131 is a wasteful number, since it uses less digits than its factorization.

4040434113131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 329589286.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 4040434113131 its reverse (1313114340404), we get a palindrome (5353548453535).

The spelling of 4040434113131 in words is "four trillion, forty billion, four hundred thirty-four million, one hundred thirteen thousand, one hundred thirty-one".