Base | Representation |
---|---|
bin | 10010010111111100001101… |
… | …11111110101011000000001 |
3 | 12022001200102110201022100011 |
4 | 21023332012333311120001 |
5 | 20243443441142442423 |
6 | 221533451100224521 |
7 | 11340111055164505 |
oct | 1113760677653001 |
9 | 168050373638304 |
10 | 40405022234113 |
11 | 11968745770279 |
12 | 464692023b141 |
13 | 197123c54a964 |
14 | 9d988368a305 |
15 | 4a10624aeb0d |
hex | 24bf86ff5601 |
40405022234113 has 8 divisors (see below), whose sum is σ = 42022328977280. Its totient is φ = 38815361760240.
The previous prime is 40405022234051. The next prime is 40405022234119. The reversal of 40405022234113 is 31143222050404.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 40405022234113 - 217 = 40405022103041 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (40405022234119) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6911564343 + ... + 6911570188.
It is an arithmetic number, because the mean of its divisors is an integer number (5252791122160).
Almost surely, 240405022234113 is an apocalyptic number.
It is an amenable number.
40405022234113 is a deficient number, since it is larger than the sum of its proper divisors (1617306743167).
40405022234113 is a wasteful number, since it uses less digits than its factorization.
40405022234113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13823134647.
The product of its (nonzero) digits is 23040, while the sum is 31.
Adding to 40405022234113 its reverse (31143222050404), we get a palindrome (71548244284517).
The spelling of 40405022234113 in words is "forty trillion, four hundred five billion, twenty-two million, two hundred thirty-four thousand, one hundred thirteen".
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