Base | Representation |
---|---|
bin | 100101101000010110… |
… | …001110101011101001 |
3 | 10212021220211010120222 |
4 | 211220112032223221 |
5 | 1130222233112213 |
6 | 30321215055425 |
7 | 2630165631251 |
oct | 455026165351 |
9 | 125256733528 |
10 | 40405363433 |
11 | 16154857646 |
12 | 79b7811575 |
13 | 3a6c051196 |
14 | 1d5436a961 |
15 | 10b73a9808 |
hex | 96858eae9 |
40405363433 has 8 divisors (see below), whose sum is σ = 40877654400. Its totient is φ = 39934825840.
The previous prime is 40405363423. The next prime is 40405363457. The reversal of 40405363433 is 33436350404.
40405363433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 40405363433 - 214 = 40405347049 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 40405363393 and 40405363402.
It is not an unprimeable number, because it can be changed into a prime (40405363423) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 391958 + ... + 484191.
It is an arithmetic number, because the mean of its divisors is an integer number (5109706800).
Almost surely, 240405363433 is an apocalyptic number.
It is an amenable number.
40405363433 is a deficient number, since it is larger than the sum of its proper divisors (472290967).
40405363433 is a wasteful number, since it uses less digits than its factorization.
40405363433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 876687.
The product of its (nonzero) digits is 155520, while the sum is 35.
The spelling of 40405363433 in words is "forty billion, four hundred five million, three hundred sixty-three thousand, four hundred thirty-three".
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