Base | Representation |
---|---|
bin | 111010110011011101110… |
… | …001111011111101101001 |
3 | 112022022111112211020000020 |
4 | 322303131301323331221 |
5 | 1012201421432114031 |
6 | 12332223310231053 |
7 | 564644334140445 |
oct | 72633561737551 |
9 | 15268445736006 |
10 | 4040990113641 |
11 | 1318857630748 |
12 | 5532074b5489 |
13 | 2340aa036250 |
14 | dd829203825 |
15 | 701ae86e096 |
hex | 3acddc7bf69 |
4040990113641 has 16 divisors (see below), whose sum is σ = 5853796440576. Its totient is φ = 2464756390656.
The previous prime is 4040990113631. The next prime is 4040990113649. The reversal of 4040990113641 is 1463110990404.
4040990113641 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 4040990113641 - 210 = 4040990112617 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 4040990113593 and 4040990113602.
It is not an unprimeable number, because it can be changed into a prime (4040990113649) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 458469625 + ... + 458478438.
It is an arithmetic number, because the mean of its divisors is an integer number (365862277536).
Almost surely, 24040990113641 is an apocalyptic number.
It is an amenable number.
4040990113641 is a deficient number, since it is larger than the sum of its proper divisors (1812806326935).
4040990113641 is a wasteful number, since it uses less digits than its factorization.
4040990113641 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 916948192.
The product of its (nonzero) digits is 93312, while the sum is 42.
The spelling of 4040990113641 in words is "four trillion, forty billion, nine hundred ninety million, one hundred thirteen thousand, six hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •