Base | Representation |
---|---|
bin | 111010110100100000100… |
… | …010000000111111011011 |
3 | 112022102101121010000200012 |
4 | 322310200202000333123 |
5 | 1012211220130412103 |
6 | 12332530353432135 |
7 | 565014153134360 |
oct | 72644042007733 |
9 | 15272347100605 |
10 | 4042110013403 |
11 | 13192817a7a40 |
12 | 55347a56b64b |
13 | 234228063827 |
14 | dd8d3c42467 |
15 | 70227d362d8 |
hex | 3ad20880fdb |
4042110013403 has 16 divisors (see below), whose sum is σ = 5335955771904. Its totient is φ = 2964419871360.
The previous prime is 4042110013391. The next prime is 4042110013481. The reversal of 4042110013403 is 3043100112404.
It is a cyclic number.
It is not a de Polignac number, because 4042110013403 - 28 = 4042110013147 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4042110013493) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1543967375 + ... + 1543969992.
It is an arithmetic number, because the mean of its divisors is an integer number (333497235744).
Almost surely, 24042110013403 is an apocalyptic number.
4042110013403 is a deficient number, since it is larger than the sum of its proper divisors (1293845758501).
4042110013403 is a wasteful number, since it uses less digits than its factorization.
4042110013403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3087937402.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 4042110013403 its reverse (3043100112404), we get a palindrome (7085210125807).
Subtracting from 4042110013403 its reverse (3043100112404), we obtain a palindrome (999009900999).
The spelling of 4042110013403 in words is "four trillion, forty-two billion, one hundred ten million, thirteen thousand, four hundred three".
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