Base | Representation |
---|---|
bin | 111010110100100110100… |
… | …011101010110011110011 |
3 | 112022102122122100021022110 |
4 | 322310212203222303303 |
5 | 1012211422021011011 |
6 | 12332544404340403 |
7 | 565016521345125 |
oct | 72644643526363 |
9 | 15272578307273 |
10 | 4042211110131 |
11 | 1319323878457 |
12 | 5534a83a4703 |
13 | 234242c9c58c |
14 | dd90343b215 |
15 | 70231b55ba6 |
hex | 3ad268eacf3 |
4042211110131 has 16 divisors (see below), whose sum is σ = 5392700906400. Its totient is φ = 2693264663040.
The previous prime is 4042211110111. The next prime is 4042211110139. The reversal of 4042211110131 is 1310111122404.
It is not a de Polignac number, because 4042211110131 - 213 = 4042211101939 is a prime.
It is a super-2 number, since 2×40422111101312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4042211110098 and 4042211110107.
It is not an unprimeable number, because it can be changed into a prime (4042211110139) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 63177945 + ... + 63241893.
It is an arithmetic number, because the mean of its divisors is an integer number (337043806650).
Almost surely, 24042211110131 is an apocalyptic number.
4042211110131 is a deficient number, since it is larger than the sum of its proper divisors (1350489796269).
4042211110131 is a wasteful number, since it uses less digits than its factorization.
4042211110131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 75686.
The product of its (nonzero) digits is 192, while the sum is 21.
Adding to 4042211110131 its reverse (1310111122404), we get a palindrome (5352322232535).
The spelling of 4042211110131 in words is "four trillion, forty-two billion, two hundred eleven million, one hundred ten thousand, one hundred thirty-one".
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