4042222113 has 4 divisors (see below), whose sum is σ = 5389629488. Its totient is φ = 2694814740.

The previous prime is 4042222109. The next prime is 4042222117. The reversal of 4042222113 is 3112222404.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (4042222109) and next prime (4042222117).

It is not a de Polignac number, because 4042222113 - 2² = 4042222109 is a prime.

It is a super-2 number, since 2×4042222113² = 32679119221652369538, which contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 4042222113.

It is not an unprimeable number, because it can be changed into a prime (4042222117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 673703683 + ... + 673703688.

It is an arithmetic number, because the mean of its divisors is an integer number (1347407372).

Almost surely, 2^4042222113 is an apocalyptic number.

It is an amenable number.

4042222113 is a deficient number, since it is larger than the sum of its proper divisors (1347407375).

4042222113 is a wasteful number, since it uses less digits than its factorization.

4042222113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1347407374.

The product of its (nonzero) digits is 768, while the sum is 21.

The square root of 4042222113 is about 63578.4720876493. The cubic root of 4042222113 is about 1592.9668000752.

Adding to 4042222113 its reverse (3112222404), we get a palindrome (7154444517).

The spelling of 4042222113 in words is "four billion, forty-two million, two hundred twenty-two thousand, one hundred thirteen".