Base | Representation |
---|---|
bin | 111010110101011101010… |
… | …100111110011000010011 |
3 | 112022112000200101222010011 |
4 | 322311131110332120103 |
5 | 1012220312240130021 |
6 | 12333215511415351 |
7 | 565051350001006 |
oct | 72653524763023 |
9 | 15275020358104 |
10 | 4043130005011 |
11 | 1319755535809 |
12 | 553704084557 |
13 | 23435b480366 |
14 | dd98d4b553d |
15 | 70287665de1 |
hex | 3ad5d53e613 |
4043130005011 has 4 divisors (see below), whose sum is σ = 4043134043352. Its totient is φ = 4043125966672.
The previous prime is 4043130005009. The next prime is 4043130005027. The reversal of 4043130005011 is 1105000313404.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 4043130005011 - 21 = 4043130005009 is a prime.
It is a super-2 number, since 2×40431300050112 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4043130005611) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 733335 + ... + 2936671.
It is an arithmetic number, because the mean of its divisors is an integer number (1010783510838).
Almost surely, 24043130005011 is an apocalyptic number.
4043130005011 is a deficient number, since it is larger than the sum of its proper divisors (4038341).
4043130005011 is a wasteful number, since it uses less digits than its factorization.
4043130005011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4038340.
The product of its (nonzero) digits is 720, while the sum is 22.
Adding to 4043130005011 its reverse (1105000313404), we get a palindrome (5148130318415).
The spelling of 4043130005011 in words is "four trillion, forty-three billion, one hundred thirty million, five thousand, eleven".
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