4043131224113 has 4 divisors (see below), whose sum is σ = 4050236903460. Its totient is φ = 4036025544768.

The previous prime is 4043131224107. The next prime is 4043131224127. The reversal of 4043131224113 is 3114221313404.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1717103606689 + 2326027617424 = 1310383^2 + 1525132^2 .

It is a cyclic number.

It is not a de Polignac number, because 4043131224113 - 2⁶ = 4043131224049 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4043131220113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3552838820 + ... + 3552839957.

It is an arithmetic number, because the mean of its divisors is an integer number (1012559225865).

Almost surely, 2^{4043131224113} is an apocalyptic number.

It is an amenable number.

4043131224113 is a deficient number, since it is larger than the sum of its proper divisors (7105679347).

4043131224113 is an equidigital number, since it uses as much as digits as its factorization.

4043131224113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7105679346.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 4043131224113 its reverse (3114221313404), we get a palindrome (7157352537517).

The spelling of 4043131224113 in words is "four trillion, forty-three billion, one hundred thirty-one million, two hundred twenty-four thousand, one hundred thirteen".