4043131300121 has 4 divisors (see below), whose sum is σ = 4065718626000. Its totient is φ = 4020543974244.

The previous prime is 4043131300073. The next prime is 4043131300127. The reversal of 4043131300121 is 1210031313404.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4043131300121 is a prime.

It is a super-2 number, since 2×4043131300121² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4043131300127) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11293662671 + ... + 11293663028.

It is an arithmetic number, because the mean of its divisors is an integer number (1016429656500).

Almost surely, 2^{4043131300121} is an apocalyptic number.

It is an amenable number.

4043131300121 is a deficient number, since it is larger than the sum of its proper divisors (22587325879).

4043131300121 is a wasteful number, since it uses less digits than its factorization.

4043131300121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22587325878.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 4043131300121 its reverse (1210031313404), we get a palindrome (5253162613525).

The spelling of 4043131300121 in words is "four trillion, forty-three billion, one hundred thirty-one million, three hundred thousand, one hundred twenty-one".