Base | Representation |
---|---|
bin | 111010110101101000000… |
… | …100100001011010100001 |
3 | 112022112111020112221000111 |
4 | 322311220010201122201 |
5 | 1012221144410211231 |
6 | 12333245430451321 |
7 | 565055665662442 |
oct | 72655004413241 |
9 | 15275436487014 |
10 | 4043310241441 |
11 | 131983824a039 |
12 | 553754503b41 |
13 | 234389907a33 |
14 | dd9a93d12c9 |
15 | 702983b94b1 |
hex | 3ad681216a1 |
4043310241441 has 4 divisors (see below), whose sum is σ = 4048235102484. Its totient is φ = 4038385380400.
The previous prime is 4043310241427. The next prime is 4043310241457. The reversal of 4043310241441 is 1441420133404.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1537342090816 + 2505968150625 = 1239896^2 + 1583025^2 .
It is a cyclic number.
It is not a de Polignac number, because 4043310241441 - 215 = 4043310208673 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4043310245441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2462429290 + ... + 2462430931.
It is an arithmetic number, because the mean of its divisors is an integer number (1012058775621).
Almost surely, 24043310241441 is an apocalyptic number.
It is an amenable number.
4043310241441 is a deficient number, since it is larger than the sum of its proper divisors (4924861043).
4043310241441 is an equidigital number, since it uses as much as digits as its factorization.
4043310241441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4924861042.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 4043310241441 its reverse (1441420133404), we get a palindrome (5484730374845).
The spelling of 4043310241441 in words is "four trillion, forty-three billion, three hundred ten million, two hundred forty-one thousand, four hundred forty-one".
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