Base | Representation |
---|---|
bin | 10010011001000101011101… |
… | …00110010000000110100001 |
3 | 12022012102220200111221012212 |
4 | 21030202232212100012201 |
5 | 20300120002334302040 |
6 | 222003512432531505 |
7 | 11343002324004305 |
oct | 1114425646200641 |
9 | 168172820457185 |
10 | 40444341322145 |
11 | 11983392327052 |
12 | 46524740b0b95 |
13 | 1974b67515117 |
14 | 9db73364bd05 |
15 | 4a20b42e4d65 |
hex | 24c8ae9901a1 |
40444341322145 has 4 divisors (see below), whose sum is σ = 48533209586580. Its totient is φ = 32355473057712.
The previous prime is 40444341322129. The next prime is 40444341322159. The reversal of 40444341322145 is 54122314344404.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 14871335057569 + 25573006264576 = 3856337^2 + 5056976^2 .
It is a cyclic number.
It is not a de Polignac number, because 40444341322145 - 24 = 40444341322129 is a prime.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4044434132210 + ... + 4044434132219.
It is an arithmetic number, because the mean of its divisors is an integer number (12133302396645).
Almost surely, 240444341322145 is an apocalyptic number.
It is an amenable number.
40444341322145 is a deficient number, since it is larger than the sum of its proper divisors (8088868264435).
40444341322145 is an equidigital number, since it uses as much as digits as its factorization.
40444341322145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8088868264434.
The product of its (nonzero) digits is 737280, while the sum is 41.
Adding to 40444341322145 its reverse (54122314344404), we get a palindrome (94566655666549).
The spelling of 40444341322145 in words is "forty trillion, four hundred forty-four billion, three hundred forty-one million, three hundred twenty-two thousand, one hundred forty-five".
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