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40522244041113 = 313507414680371
BaseRepresentation
bin10010011011010110100011…
…11101100010100110011001
312022110212222212020002111120
421031223101331202212121
520302404023433303423
6222103354550315453
711351430661125042
oct1115532175424631
9168425885202446
1040522244041113
1111a0342939191a
124665595658b89
13197c300ca1833
14a01403a478c9
154a41235d6ee3
hex24dad1f62999

40522244041113 has 4 divisors (see below), whose sum is σ = 54029658721488. Its totient is φ = 27014829360740.

The previous prime is 40522244041109. The next prime is 40522244041129. The reversal of 40522244041113 is 31114044222504.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 40522244041113 - 22 = 40522244041109 is a prime.

It is not an unprimeable number, because it can be changed into a prime (40522244041133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6753707340183 + ... + 6753707340188.

It is an arithmetic number, because the mean of its divisors is an integer number (13507414680372).

Almost surely, 240522244041113 is an apocalyptic number.

It is an amenable number.

40522244041113 is a deficient number, since it is larger than the sum of its proper divisors (13507414680375).

40522244041113 is a wasteful number, since it uses less digits than its factorization.

40522244041113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13507414680374.

The product of its (nonzero) digits is 30720, while the sum is 33.

Adding to 40522244041113 its reverse (31114044222504), we get a palindrome (71636288263617).

The spelling of 40522244041113 in words is "forty trillion, five hundred twenty-two billion, two hundred forty-four million, forty-one thousand, one hundred thirteen".

Divisors: 1 3 13507414680371 40522244041113