4053424521331 has 4 divisors (see below), whose sum is σ = 4066211349792. Its totient is φ = 4040637692872.

The previous prime is 4053424521301. The next prime is 4053424521343. The reversal of 4053424521331 is 1331254243504.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4053424521331 - 2⁷ = 4053424521203 is a prime.

It is a super-3 number, since 3×4053424521331³ (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4053424521301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6393413755 + ... + 6393414388.

It is an arithmetic number, because the mean of its divisors is an integer number (1016552837448).

Almost surely, 2^{4053424521331} is an apocalyptic number.

4053424521331 is a deficient number, since it is larger than the sum of its proper divisors (12786828461).

4053424521331 is a wasteful number, since it uses less digits than its factorization.

4053424521331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12786828460.

The product of its (nonzero) digits is 172800, while the sum is 37.

Adding to 4053424521331 its reverse (1331254243504), we get a palindrome (5384678764835).

The spelling of 4053424521331 in words is "four trillion, fifty-three billion, four hundred twenty-four million, five hundred twenty-one thousand, three hundred thirty-one".