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40541334441 = 313513778147
BaseRepresentation
bin100101110000011100…
…111010101110101001
310212122101200011202020
4211300130322232221
51131012040200231
630342513255053
72633436441216
oct456034725651
9125571604666
1040541334441
1116214587683
127a35264489
133a9127a6ba
141d68442b0d
1510c42b7396
hex97073aba9

40541334441 has 4 divisors (see below), whose sum is σ = 54055112592. Its totient is φ = 27027556292.

The previous prime is 40541334439. The next prime is 40541334521. The reversal of 40541334441 is 14443314504.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 40541334441 - 21 = 40541334439 is a prime.

It is not an unprimeable number, because it can be changed into a prime (40541334241) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6756889071 + ... + 6756889076.

It is an arithmetic number, because the mean of its divisors is an integer number (13513778148).

Almost surely, 240541334441 is an apocalyptic number.

It is an amenable number.

40541334441 is a deficient number, since it is larger than the sum of its proper divisors (13513778151).

40541334441 is a wasteful number, since it uses less digits than its factorization.

40541334441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13513778150.

The product of its (nonzero) digits is 46080, while the sum is 33.

Adding to 40541334441 its reverse (14443314504), we get a palindrome (54984648945).

The spelling of 40541334441 in words is "forty billion, five hundred forty-one million, three hundred thirty-four thousand, four hundred forty-one".

Divisors: 1 3 13513778147 40541334441