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40543344433 = 51717840523
BaseRepresentation
bin100101110000100100…
…100101011100110001
310212122112110021221101
4211300210211130301
51131013044010213
630343024324401
72633462512234
oct456044453461
9125575407841
1040543344433
111621572a829
127a35a73701
133a91802547
141d6880741b
1510c4562bdd
hex970925731

40543344433 has 4 divisors (see below), whose sum is σ = 40551190128. Its totient is φ = 40535498740.

The previous prime is 40543344371. The next prime is 40543344437. The reversal of 40543344433 is 33444334504.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 40543344433 - 29 = 40543343921 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 40543344392 and 40543344401.

It is not an unprimeable number, because it can be changed into a prime (40543344437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3915091 + ... + 3925432.

It is an arithmetic number, because the mean of its divisors is an integer number (10137797532).

Almost surely, 240543344433 is an apocalyptic number.

It is an amenable number.

40543344433 is a deficient number, since it is larger than the sum of its proper divisors (7845695).

40543344433 is an equidigital number, since it uses as much as digits as its factorization.

40543344433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7845694.

The product of its (nonzero) digits is 414720, while the sum is 37.

Adding to 40543344433 its reverse (33444334504), we get a palindrome (73987678937).

The spelling of 40543344433 in words is "forty billion, five hundred forty-three million, three hundred forty-four thousand, four hundred thirty-three".

Divisors: 1 5171 7840523 40543344433